How should the ball of different ball diameters match?

The reasonable ratio of the ball diameter has two aspects. One is to determine which balls of diameter are installed, and the other is to determine the proportion of balls of various diameters, and the actual mass. In theory, in order to achieve a good grinding effect, it should be ensured that the mass ratio of various balls in the grinding machine is compatible with the particle size composition of the material to be ground. Ball mills in our production sites are equipped with a variety of balls of different sizes to process mixed materials of different sizes. For new processing plant, due to the lack of actual data, multi-reference similar beneficiation plant plus the actual proportion ball, the production process to make the appropriate adjustments. For the production of the concentrating mill grinding machine ball can be summarized as follows: (1) first take the grinding machine to give the ore sample (usually take the new ore and return sand sample, and then proportionally sample) for screening, Divided into several fractions, such as 18~12, 12~10, 10~8, 8~6, etc., weigh each grade, calculate the mass percentage (yield) of each grade, such as nok="f" gradientshapeok=" t" o:co nnecttype="rect">, ,......etc; (2) use the upper limit of each level of granularity (such as 18, 12, 10, 8, etc.) or the upper and lower averages (such as 15, 11 9, 7 ..., etc.) Refer to Table 18 or use the formula to determine the diameter of the ball to be added at each particle level, such as, (3) according to the principle that the mass ratio of the ball of various sizes is compatible with the particle size composition of the grinding material. Determine the percentage of balls of various sizes to the total mass of the ball, corresponding to 'D18=18-12, 'D12=12-10, 'D10=10-8, 'D8= 8-6..." (4) The calculation results are adjusted appropriately. Due to the actual ball distribution, too small balls are not matched, only a few balls are selected. Therefore, the calculated small diameter balls can be proportionally distributed to the larger balls to re-determine the balls at all levels. Quality

Where G is the total mass of the ball, t; D - the inner diameter of the barrel of the ball mill, m; L - the effective length of the barrel of the ball mill, m; - the filling rate of the medium, %; - the bulk density of the ball, t / M3. 2 According to the adjusted ball ratio of each level, the mass of each ball is calculated as GD18=G·D18, GD12=G·D12, GD10=G·D10, GD8=G·D8...... [Example] Value="1500" unitname="mm" w:st="on">1500mm×value="3000" unitname="mm" w:st="on">3000mm wet lattice ball mill to load the ball, determine the filling rate = 50%, cast steel ball = 4.5t / m3, the mill is treated as medium hard ore. 1) The results of the complete ore screening of the grinding machine are shown in Table 19. Table 19 Total ore screening results
Size (mm) Yield(%) Size (mm) Yield(%)
18~12 18-12 = 20 6 to 4 6-4 = 5
12~10 12-10 = 40 4~2 4-2 = 4
10~8 10-8 = 15 2 to 1 2-1 = 4
8~6 8-6 = 8 1~0 1-0 = 4
2) Calculate the ball diameter to be matched according to the upper limit of each level and round up, see Table 20. Table 20 should be equipped with the size of the ball diameter
Size (mm) Ball diameter (mm) Size (mm) Ball diameter (mm)
18~12 D 18 =120 6 to 4 D 6 =70
12~10 D 12 =100 4~2 D 4 = 60
10~8 D 10 =90 2 to 1 D 2 = 50
8~6 D 8 =80 1~0 D 1 =40
3) The mass percentage of various balls is shown in Table 21. Table 21 Percentage of mass of various balls
Ball diameter (mm) Quality ratio (%) Ball diameter (mm) Quality ratio (%)
120 20 70 5
100 40 60 4
90 15 50 4
80 8 40 4
If it is determined that only 120, 100, 80, and 60 balls are added, the ratio of 90, 70, 50, and 40 balls can be appropriately adjusted to other balls. The results of this example are shown in Table 22. Table 22 Percentage of mass of various balls after adjustment
Ball diameter (mm) Quality ratio (%) Ball diameter (mm) Quality ratio (%)
120 30 80 13
100 45 60 12
4) Calculate the total mass G of the added ball:

5) Calculate the mass of each ball should be added G120=G·120=11.928×0.3=3.58 (t) G100=G· 100=11.928×0.45=5.37 (t) G80=G· 80=11.928×0.13=1.55 ( t) G60=G· 60=11.928×0.12=1.43 (t) 6) According to the calculation result, the ball is weighed.

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